(B^2+6b)/2=36

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Solution for (B^2+6b)/2=36 equation: 



(^2+6B)/2=36

We move all terms to the left:

(^2+6B)/2-(36)=0

We multiply all the terms by the denominator


(^2+6B)-36*2=0

We add all the numbers together, and all the variables

(^2+6B)-72=0

We get rid of parentheses

6B-72+^2=0

We add all the numbers together, and all the variables

6B=0

B=0/6

B=0

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